In this article, we have given MP Board Solutions Class 10th Science Chapter 12 Electricity solution pdf.
MP Board Class 10th Science Chapter 12 Multiple Choice Questions
SI unit of an electric current is equal to
(a) 6 × 108 C (b) 9.8 × 1010 C (c) 1.6 × 10-19 C (d) None of these
Answer: (d) None of these
Which materials have changing resistivity?
(a) Conductors (b) Semiconductors (c) Non-metals (d) Super metals
Answer: (b) Semiconductors
If wire in a circuit is doubled its resistivity will be?
(a) Two times (b) Ten times (c) Zero (d) half
Answer: (d) half
A wire used in circuit must be
(a) Highly resistant (b) Non resistance (c) Have high melting point (d) None of these
Answer: (b) Non resistance
A heating w ire must have
(a) High melting point (b) High conductivity to heat (c) Both (d) None
Answer: (b) High conductivity to heat
SI unit of resistance is:
(a) Coulomb (b) Ampere (c) Ohm (d) Ohm – meter
Answer: (c) Ohm
Relation of potential difference and current is represented by:
(a) Joule’s law (b) Ohm’s law (c) Dalton’s law (d) None
Answer: (b) Ohm’s law
Formula which represents the relation among potential difference and current following in a circuit is:
(a) V = IR (b) V = I/R (c) l = Q/t (d) R = p lA
Answer: (a) V = IR
Kilo watt is a unit for:
(a) Power (b) Electrical energy commercial (c) Resistance (d) Current flow in circuit
Answer: (a) Power
Which one has less resistance?
(a) 10 watt bulb (b) 15 watt LED (c) 60 watt bulb (d) 60 watt LED.
Answer: (a) 10 watt bulb
In which type of combinations resistance is more?
(a) Series Combination (b) Parallel combination (c) both (d) Single resistance unit.
Answer: (a) Series Combination
Joule’s law formulation is
(a) H = IRT (b) H = I2RT (c) P = VI (d) RT = PV
Answer: (d) RT = PV
Hardest metal which can resist maximum heat is:
(a) Lead (b) Tungsten (c) Silver (d) Carbon
Answer: (b) Tungsten
If current passing a circuit is 10 A and wire is connected to 100 volt line resistant in the wire will be:
(a) 10 A (b) 10 Ω (c) 100 Ω (d) O Ω
Answer: (b) 10 Ω
An insulator has a resistivity equals to:
(a) 10-8 Ω m (b) 10 Ω m (c) 5 Ω m (d) 10-18 Ω
Answer: (a) 10-8 Ω m
If resistors are arranged in parallel with value 1 Ω, 2 Ω and 3 Ω Total resistant will be:
(a) more than 3 Ω (b) less than 3 Ω (c) less than 1 Ω (d) equal to 1 Ω
Answer: (b) less than 3 Ω
The changing 1 kWh to joule will be equal to
(a) 3.6 × 106 J (b) 3.6 × 10-6 J (c) 1.6 × 106 J (d) 1 × 106 J
Answer: (a) 3.6 × 106 J.